3/5(a^2-5a+25)

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Solution for 3/5(a^2-5a+25) equation: 


a in (-oo:+oo)

(3/5)*(a^2-(5*a)+25) = 0

(3/5)*(a^2-5*a+25) = 0

3/5*(a^2-5*a+25) = 0

a^2-5*a+25 = 0

a^2-5*a+25 = 0

DELTA = (-5)^2-(1*4*25)

DELTA = -75

DELTA < 0

1 = 0

3/5 = 0

a belongs to the empty set

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